衡水金卷先享题调研卷2022语文 答案

衡水金卷先享题调研卷2022语文 答案，目前我们已经整理了衡水金卷先享题调研卷2022语文 答案的各科答案和试卷，更多试卷答案请关注本答案网。

第一节One possible versionDear Sir/MadamKnowing the International Book Fair will be held nextweek in our city and that some volunteers are needed. I amwriting to recommend myselfThe following are my advantages. First of all, I speakEnglish so fluently that I have no difficulty communicatingwith foreigners. Secondly, as a monitor, I always organizeall kinds of social activities. More importantly, I am a reg-stered volunteer, so I have gained rich experience in volentering.I would appreciate it if I were given a chance. Lookingforward to your early reply.Yours.Li Hi第二节One possible versionLater that evening, my son came up to me, his handbehind his back. "I have something for you, Daddy, "hesaid. Beyond my expectation, he handed me a KenGriffey, Jr. card. He'd taken a pair of scissors and cutone copy of the Griffey off from the box. Now you don'thave to look for it anymore, "he said. Hearing what hesaid,I was shocked, and moved to tears. At once, the hugI gave him was the best price I ever paid for a cardI continued collecting, and even ended up buying andselling some old and valuable cards. However, there wasone card that I would never trade, which was a KenGriffey, Jr. card. Up to now, I still keep that Griffey, Jrcard, even if it has had the rough borders and the shabbycorners, and there is only a plain and simple board on theback. That is because that card. to me, is what baseball isall about. More importantly, it's also what loveall about

38.(12分,每空2分)(1)1/32(2)紫花白花=1:1紫花白花=31:1紫花:白花=7:1紫花:白花=7:11/9【解析】(1)如果假设①正确,则亲本的基因型为AA和aa,F1的基因型为Aa,F2中白花植株所占的比率1/(63+1)=164。F1紫花植株产生的雌配子中a的概率为1/2,A配子的概率为1/2,故F1紫花植株产生的可育雄配子中a的概率是(164)/(1/2)=/32(2)验证上述①假设当E1作为母本进行测交时,即Aa×aa,则雌配子中a的概率为1/2,A的概率为1/2,雄配子的基因组成为a,故子代的基因型及比例为Aaa=1:1子代表现型及比例为紫花:白花=1:1当F1作为父本进行测交时,即Aaxa,则雄配子中a配子的概率为1/32,A配子的概率为31/32,雌配子的基因组成为a,故子代的基因型及氵比例为Aa:aa=(31/32):(1/32)=31:1,子代表现型及比例为紫花白花=31:1。验证上述②假设:不管F1作为母本,还是父本,进行测交时,均为AaB-bCc× aabbcc,子代中只有基因型为abec的植株为白花植株,其余均为紫花植株。子代中基因型为abbc植株所占的比例为1/2×1/2×1/2=1/8,故紫花:白花=(1-1/8):(1/8)=7:1。如果实验证明假设②是正确的,F1紫花植株进行自交,即 AaBbCc氵AaBbCc,F2中的紫花植株所占的比例为63/(63+1)=63/64,其中纯种所占的比例为(1/2×1/2×1/2-1/64)/(63/64)=1/9。