2023学英语周报八年级下册（基础）28期答案

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第二节书面表达【写作思路】根据试题要求,考生需要写一篇记叙文,记述身边一位值得尊敬和爱戴的人。首先考生需要介绍自己最尊敬和爱戴的人是谁,简单地介绍一下他(她)。然后,陈述为什么他(她)值得尊敬和爱戴。最后,可以对前文进行一个总结,使文章结构严谨。本文的写作重点在"尊敬和爱戴的原因",考生可围绕这个要点适当拓展,从性格特点、处事风格等方面展开写作。【范文赏读】The most beloved and respected person around me is my teacher, Ms LiThough she has been teaching English for twenty years, she is still passionateabout teaching. She is kind and considerate towards us just like our dear motherWe all respect her because she always tries new ways to make her classes livelyand interesting. Hardworking and knowledgeable, she is one of the best teachersin our school. When we have a problem, we will turn to her for help. She alwaystalks to us patiently and helps us to find a solution. In our eyes, she is not onlyour teacher, but also our best friend. Those are why she deserves our respect【亮点词句】亮点词汇: beloved, respected, be passionate about, be consideratetowards, turn to sb. for help, in one's eyes亮点句式:Why引导的表语从句( why she deserves our respect)

15.C【解析】由反应2KCuO2+8HCl2KCI-+2CuCl2+Cl2↑+4H2O可知,Cl元素化合价升高,由1价变为0价,8 mol HCl参与反应共转移2mol电子根据电子得失守恒,Cu元素化合价应降低,CuCl2中Cu元素为+2价,设KCuO2中铜元素的化合价为r,则(x-2)×2=2,解得x=3,则KCuO2中铜元素为3价,A正确;配平方程式得2Na1O2+5 NaSO12Na2SO1+3 NaHSO4+H2O+I2,所以氧化剂前的化学计量数是2B正确;配平方程式得CO+PC2+H2O=Pd+CO2+2HCl.生成1 mol CO2时转移电子2mol.因此每转移1mol电子,生成0.5 mol CO2,C错误;氧化剂为MnO7,还原剂为Cus,设MnO7为r mol CuS为ymol,根据电子守恒得x×(7-2)=y×[4-(-2)],x:y=6:5.所以氧化剂与还原剂的物质的量之比为6:5·D正确。故选C。

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