2023八年级上册hn版英语周报答案第七期

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第二节书面表达【写作思路】根据试题要求,考生需要写一篇记叙文,记述身边一位值得尊敬和爱戴的人。首先考生需要介绍自己最尊敬和爱戴的人是谁,简单地介绍一下他(她)。然后,陈述为什么他(她)值得尊敬和爱戴。最后,可以对前文进行一个总结,使文章结构严谨。本文的写作重点在"尊敬和爱戴的原因",考生可围绕这个要点适当拓展,从性格特点、处事风格等方面展开写作。【范文赏读】The most beloved and respected person around me is my teacher, Ms LiThough she has been teaching English for twenty years, she is still passionateabout teaching. She is kind and considerate towards us just like our dear motherWe all respect her because she always tries new ways to make her classes livelyand interesting. Hardworking and knowledgeable, she is one of the best teachersin our school. When we have a problem, we will turn to her for help. She alwaystalks to us patiently and helps us to find a solution. In our eyes, she is not onlyour teacher, but also our best friend. Those are why she deserves our respect【亮点词句】亮点词汇: beloved, respected, be passionate about, be consideratetowards, turn to sb. for help, in one's eyes亮点句式:Why引导的表语从句( why she deserves our respect)

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18.I.(1)H2+N2O=N2+H2O(1分)(2)不利于降低溶液中的含氮量(2分)(3)不能(1分)氢气在单原子铂的催化作用下失电子生成H,如果没有单原子铂的催化作用反应很难进行(1分)Ⅱ.(1)负(1分)NO2+NO-cN2O5(1分)()2+4e+2N2O5=4NO3(1分)(2)80.4(2分)【解析】1.(1)由图可知.Ir表面上的氢气与N2O发生反应,生成氮气和水,故发生反应的化学方程式为H:+N2O-N, -+ H; O(2)由图可知,Pt颗粒使NO7转化为NH4,若导电基体上的Pt颗粒增多,造成的后果是NO3更多的转化为NH存在溶液中,不利于降低溶液中含氮量(3)因为氢气在单原子铂的催化作用下失电子生成H+.如果没有单原子铂的催化作用反应很难进行。(4)由图可知.甲池为NO2、O2和熔融KNO3制成的燃料电池,工作时,石墨Ⅰ上NO2转化成N2O3,是氧化反应,故石墨Ⅰ为原电池的负极,电极反应式是NO2+NO3-eN2O3,则石墨Ⅱ是原电池的正极,正极上发生还原反应,故电极反应式为O2+4e-+2N2OANOT(5)若用10A的电流电解60min后,阴极通过的总电量为10A×60minx60s·min-1=36000C则阴极通过的电子的物质的量为36000C96500C·mol-l;则理论上36000C阴极得到Ag的质量为96500C·mo×108g·mol-≈0.3g.乙中阴极得到32.4gAg,则该电解池的电解效率为324g×100%≈80.4%。40.3g

2023八年级上册hn版英语周报答案第七期

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