学英语2021-2022学年高三(新高考)综合能力提升版第26期答案

学英语2021-2022学年高三(新高考)综合能力提升版第26期答案，目前我们趣对答案已经整理了学英语2021-2022学年高三(新高考)综合能力提升版第26期答案的各科答案和试卷，更多试卷答案请关注本趣对答案。

4.(1)BCE【解析】由题知b光在AC上发生了全反射,恰好发生全反射时,AC右侧亦无b光射出,此时n0由几何关系可知i=37°,得出n0故棱镜对b光的折射率大于等于一,A错误;k光在AC上发生反射因a光的折射率小于b光,二光以相同的入射角射到界面BC上同一点,故a光在b光的右侧,B正确;若k光经M点斜向下入射,当a光射到AC上入射角大于等于其临界角时,将发生全反射,C正确;b光的折射率大于a光,故b光的频率大于a光,b光的波长小于a光,使用a光做双缝干涉实验时,相邻亮条纹间距较大,D错误;由v=一可知,在棱镜中a光的速度大于b光,故由M至N的过程中,a光的传播时间小于b光,E正确(2)(|)6(0.375+2.25k)m/s(k=0,1i ) a=5t-cos 5rI(m/s)【解析】()由图知振幅A=10cm,x=0处质点的振动方程为y=10sin(t +o)(cm) O令t=0,结合波向x轴正方向传播可知6x2=15cm处质点的振动方程为y=1Osin( ot+A·2x/ccm且A>x2,t=0时,y=-10cm解得A=0.45m③x1=0处的质点,t1=0.2s时有+2kx(k=0,1,2,…)A结合v=④解得v=(0.375+2.25k)m/s(k=0,1,2,……)⑤(i)k=0时,T=1.2s,a=-rrad/s⑥x2处质点的振动方程为y=10sin a即y=-10 cos (t(cm)⑦根据瞬时速度的定义有lim△y△根据加速度的定义有lim△5r25联立⑤⑦③②式解得a=1883(m/s)0评分标准:本题共10分。①②③④⑤⑥⑦⑧⑨⑩式各1分。

节《满分25分)Afer being X-rayed, I was informed to have a surgery as soon as passible. Given my lack of money on methe hospital staff tried to contact my relatives living nearby but in vain. Seeing my embarrassment and suffering,worry.I am here..且epagain and again and finally got in contact with my niece. My operation went on smoothly and all the time a sense ofwarmth flooded mehim. It turned out that he had walked away without leaving a word soon after my niece arrived. We intended to findhim to express our gratitude for his timely and generous help, without which I couldn 't have recovereHowever, all of our attempts to find him failed. His help and generosity made a difference to us. We are detto pass on his act of kindness to people stuck in trouble